nexttoward
计算x在y方向的下个浮点数。
接口定义
C interface:
float nexttowardf(float x, long double y);
double nexttoward(double x, long double y);
参数
参数名 |
类型 |
描述 |
输入/输出 |
|---|---|---|---|
x |
|
表示输入数据的浮点值。 |
输入 |
y |
|
表示输入数据的浮点值。 |
输入 |
返回值
返回x的在y方向上的下一个浮点值。
- 输入x=y,返回x。
- 输入x或者y等于nan,返回nan。
依赖
C: "km.h"
示例
C interface:
// typical usage
double x1 = 1.0, x2 = 1.0;
double y1 = 1.0, y2 = 1.1;
double z1 = 1.0, z2 = 0.9;
// special handling
double e = INFINITY, f = -INFINITY, g = NAN;
// print result
printf("\t/*\n");
printf("\t * nexttoward(1.0, 1.0) = %a\n", nexttoward(x1, (long double)y1));
printf("\t * nexttoward(1.0, 1.1) = %a\n", nexttoward(y1, (long double)y2));
printf("\t * nexttoward(1.0, 0.9) = %a\n", nexttoward(z1, (long double)z2));
printf("\t * nexttoward(INFINITY, 0) = %a\n", nexttoward(e, 0.0));
printf("\t * nexttoward(-INFINITY, 1.0) = %a\n", nexttoward(f, x1));
printf("\t * nexttoward(NAN, 1.0) = %a\n", nexttoward(g, x1));
printf("\t * nexttoward(NAN, INFINITY) = %a\n", nexttoward(g, e));
printf("\t */\n");
return 0;
/*
* nexttoward(1.0, 1.0) = 0x1p+0
* nexttoward(1.0, 1.1) = 0x1.0000000000001p+0
* nexttoward(1.0, 0.9) = 0x1.fffffffffffffp-1
* nexttoward(INFINITY, 0) = 0x1.fffffffffffffp+1023
* nexttoward(-INFINITY, 1.0) = -0x1.fffffffffffffp+1023
* nexttoward(NAN, 1.0) = nan
* nexttoward(NAN, INFINITY) = nan
*/
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