scalbln
计算x * 2^y的值。
接口定义
C interface:
float scalblnf(float x, long int y);
double scalbln(double x, long int y);
long double scalblnl(long double x, long int y);
参数
参数名 |
类型 |
描述 |
输入/输出 |
|---|---|---|---|
x |
|
表示输入数据的浮点值。 |
输入 |
y |
|
表示输入数据的长整数值。 |
输入 |
返回值
- 返回x * 2^y的值,发生溢出时,返回±∞(符号与x保持一致)。
依赖
C: "km_l9.h"
示例
C interface:
// typical usage
double x1 = 0.0, x2 = -0.0, x3 = 2.0;
long int y1 = 2, y2 = 3, y3 = 4, y4 = 5, y5 = 1100;
// special handing
double a = INFINITY, b = -INFINITY, c = NAN;
printf("scalbln(0.0, 2) = %.15f\n", scalbln(x1, y1));
printf("scalbln(-0.0, 3) = %.15f\n", scalbln(x2, y2));
printf("scalbln(2.0, 4) = %.15f\n", scalbln(x3, y3));
printf("scalbln(2.0, 5) = %.15f\n", scalbln(x3, y4));
printf("scalbln(2.0, 1100) = %.15f\n", scalbln(x3, y5));
printf("scalbln(INFINITY, 2) = %.15f\n", scalbln(a, y1));
printf("scalbln(-INFINITY, 2) = %.15f\n", scalbln(b, y1));
printf("scalbln(NAN, 2) = %.15f\n", scalbln(c, y1));
/*
* scalbln(0.0, 2) = 0.000000000000000
* scalbln(-0.0, 3) = -0.000000000000000
* scalbln(2.0, 4) = 32.000000000000000
* scalbln(2.0, 5) = 64.000000000000000
* scalbln(2.0, 1100) = inf
* scalbln(INFINITY, 2) = inf
* scalbln(-INFINITY, 2) = -inf
* scalbln(NAN, 2) = nan
*/
父主题: 指数和对数函数