ctanh

计算复数的双曲正切值。

接口定义

C interface：

float complex ctanhf(float complex x);

double complex ctanh(double complex x);

参数

参数名	类型	描述	输入/输出
x	在ctanhf中，x是复数单精度浮点类型。	表示输入数据的浮点值。	输入
x	在ctanh中，x是复数双精度浮点类型。	表示输入数据的浮点值。	输入

返回值

返回x的双曲正切结果y。

特殊值说明如下所示。

输入值实部（x.real）	输入值虚部（x.imag）	输出值实部（y.real）	输出值虚部（y.imag）
0.0	0.0	0.0	0.0
0.0	-0.0	0.0	-0.0
0.0	inf	0.0	nan
0.0	-inf	0.0	nan
0.0	nan	0.0	nan
0.0	-nan	0.0	nan
-0.0	0.0	-0.0	0.0
-0.0	-0.0	-0.0	-0.0
-0.0	inf	-0.0	nan
-0.0	-inf	-0.0	nan
-0.0	nan	-0.0	nan
-0.0	-nan	-0.0	nan
inf	0.0	1.0	0.0
inf	-0.0	1.0	-0.0
inf	inf	1.0	0.0
inf	-inf	1.0	-0.0
inf	nan	1.0	0.0
inf	-nan	1.0	-0.0
-inf	0.0	-1.0	0.0
-inf	-0.0	-1.0	-0.0
-inf	inf	-1.0	0.0
-inf	-inf	-1.0	-0.0
-inf	nan	-1.0	0.0
-inf	-nan	-1.0	-0.0
nan	0.0	nan	0.0
nan	-0.0	nan	-0.0
nan	inf	nan	nan
nan	-inf	nan	nan
nan	nan	nan	nan
nan	-nan	nan	nan
-nan	0.0	-nan	0.0
-nan	-0.0	-nan	-0.0
-nan	inf	nan	nan
-nan	-inf	nan	nan
-nan	nan	nan	nan
-nan	-nan	nan	nan

依赖

C: "kc.h"

示例

C interface：

    // typical usage
    double x1 = INFINITY, y1 = INFINITY;
    double x2 = 2.0, y2 = 3.0;
    double x3 = -2.5, y3 = -3.4;
    double x4 = NAN, y4 = NAN;
    double x5 = 0, y5 = 0;
    double complex z1 = ctanh(__builtin_complex(x1, y1));
    double complex z2 = ctanh(__builtin_complex(x2, y2));
    double complex z3 = ctanh(__builtin_complex(x3, y3));
    double complex z4 = ctanh(__builtin_complex(x4, y4));
    double complex z5 = ctanh(__builtin_complex(x5, y5));
    // print result
    printf("/*\n");
    printf(" * ctanh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x1, y1, __real__(z1), __imag__(z1));
    printf(" * ctanh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x2, y2, __real__(z2), __imag__(z2));
    printf(" * ctanh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x3, y3, __real__(z3), __imag__(z3));
    printf(" * ctanh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x4, y4, __real__(z4), __imag__(z4));
    printf(" * ctanh(%.2f + %.2f*I) = %.6f + %.6f*I\n", x5, y5, __real__(z5), __imag__(z5));
    printf(" **/\n");
 
   /*
    * ctanh(inf + inf*I) = 1.000000 + 0.000000*I
    * ctanh(2.00 + 3.00*I) = 0.965386 + -0.009884*I
    * ctanh(-2.50 + -3.40*I) = -0.988331 + -0.006581*I
    * ctanh(nan + nan*I) = nan + nan*I
    * ctanh(0.00 + 0.00*I) = 0.000000 + 0.000000*I
    **/

父主题： 复数函数