scalbn
计算x * 2^y的值。
接口定义
C interface:
float scalbnf(float x, int y);
double scalbn(double x, int y);
long double scalbnl(long double x, int y);
参数
参数名 |
类型 |
描述 |
输入/输出 |
---|---|---|---|
x |
|
表示输入数据的浮点值。 |
输入 |
y |
|
表示输入数据的整数值。 |
输入 |
返回值
- 返回x * 2^y的值,发生溢出时,返回±∞(符号与x保持一致)。
依赖
C: "km_l9.h"
示例
C interface:
// typical usage double x1 = 0.0, x2 = -0.0, x3 = 2.0; long int y1 = 2, y2 = 3, y3 = 4, y4 = 5, y5 = 1100; // special handing double a = INFINITY, b = -INFINITY, c = NAN; printf("scalbn(0.0, 2) = %.15f\n", scalbn(x1, y1)); printf("scalbn(-0.0, 3) = %.15f\n", scalbn(x2, y2)); printf("scalbn(2.0, 4) = %.15f\n", scalbn(x3, y3)); printf("scalbn(2.0, 5) = %.15f\n", scalbn(x3, y4)); printf("scalbn(2.0, 1100) = %.15f\n", scalbn(x3, y5)); printf("scalbn(INFINITY, 2) = %.15f\n", scalbn(a, y1)); printf("scalbn(-INFINITY, 2) = %.15f\n", scalbn(b, y1)); printf("scalbn(NAN, 2) = %.15f\n", scalbn(c, y1)); /* * scalbn(0.0, 2) = 0.000000000000000 * scalbn(-0.0, 3) = -0.000000000000000 * scalbn(2.0, 4) = 32.000000000000000 * scalbn(2.0, 5) = 64.000000000000000 * scalbn(2.0, 1100) = inf * scalbn(INFINITY, 2) = inf * scalbn(-INFINITY, 2) = -inf * scalbn(NAN, 2) = nan */
父主题: 指数和对数函数