fmod
Compute the modulus of x with respect to y, that is x modulo y. x and y are of the floating-point type.
Interface Definition
C interface:
float fmodf(float x, float y);
double fmod(double x, double y);
Parameters
Parameter |
Type |
Description |
Input/Output |
|---|---|---|---|
x |
|
Floating-point value of the input data |
Input |
y |
|
Floating-point value of the input data |
Input |
x |
|
Floating-point value of the input data |
Input |
y |
|
Floating-point value of the input data |
Input |
Return Value
Return the result of x modulo y.
- If x is any value and y is ±0 or NaN, the return value is NaN.
- If x is ±0 and y is not ±0 or nan, the return value is ±0.
- If x is ±∞ or nan and y is any value, the return value is nan.
Dependencies
C: "km.h"
Examples
C interface:
// typical usage
float x1 = -1.0, x2 = 2.0, x3 = 3.0, x4 = 4.0;
float y1 = 4.0, y2 = -4.0, y3 = -3.0, y4 = 3.0;
// special handing
float a = 0.0, b = INFINITY, c = -INFINITY, d = NAN;
// print result
printf("fmodf(-1.0, 4.0) = %.6f\n", fmodf(x1, y1));
printf("fmodf(2.0, -4.0) = %.6f\n", fmodf(x2, y2));
printf("fmodf(3.0, -3.0) = %.6f\n", fmodf(x3, y3));
printf("fmodf(4.0, 3.0) = %.6f\n", fmodf(x4, y4));
printf("fmodf(1.0, 0.0) = %+.6f\n", fmodf(x1, a));
printf("fmodf(INFINITY, 1.0) = %+.6f\n", fmodf(b, x1));
printf("fmodf(-INFINITY, -1.0) = %+.6f\n", fmodf(c, -x1));
printf("fmodf(1.0, -INFINITY) = %+.6f\n", fmodf(x1, c));
printf("fmodf(1.0, NAN) = %+.6f\n", fmodf(x1, d));
printf("fmodf(NAN, -1.0) = %+.6f\n", fmodf(d, -x1));
/*
* fmodf(-1.0, 4.0) = -1.000000
* fmodf(2.0, -4.0) = 2.000000
* fmodf(3.0, -3.0) = 0.000000
* fmodf(4.0, 3.0) = 1.000000
* fmodf(1.0, 0.0) = -nan
* fmodf(INFINITY, 1.0) = -nan
* fmodf(-INFINITY, -1.0) = -nan
* fmodf(1.0, -INFINITY) = +1.000000
* fmodf(1.0, NAN) = +nan
* fmodf(NAN, -1.0) = +nan
* */
Parent topic: Function Syntax