v?exp
Compute the element-wise base-e exponential of a vector.
Interface Definition
C interface:
void vsexp(const int len, const float* src, float* dst);
void vdexp(const int len, const double* src, double* dst);
Fortran interface:
CALL VSEXP(LEN, SRC, DST);
CALL VDEXP(LEN, SRC, DST);
Parameters
Parameter |
Type |
Description |
Input/Output |
|---|---|---|---|
len |
Integer |
Number of elements in the input vector. If len ≤ 0, the system displays a message indicating that the value of len is invalid. |
Input |
src |
|
Input vector src with length len. If the pointer is null, the system prompts a null pointer error. |
Input |
dst |
|
Output vector dst with length len. If the pointer is null, the system prompts a null pointer error. |
Output |
Return Value
- The exponent y of x with e as the base is returned for each operation value. y ∈ (0, +INF)
- If the input is +0, the return value is +1.
- If the input is –0, the return value is +1.
- If the input of expf is greater than 0x1.62e42ep6f (about 88), the return value is +∞. If the input of exp is greater than 0x1.62p9 (about 708), the return value is +∞.
- If the input of expf is less than -0x1.9fe368p6f (about -104), the return value is +0. If the input of exp is less than -0x1.62p9 (about -708), the return value is +0.
- If the input is +∞, the return value is +∞.
- If the input is -∞, the return value is +0.
- If the input is NaN, the return value is NaN.
Dependencies
C: "kvml.h"
Fortran: "kvml.f03"
Examples
C interface:
int i, len = 4;
float src[len] = {0.0f, INFINITY, NAN, 2.0f};
float* dst = (float*)malloc(sizeof(float) * len);
if (dst == NULL) {
printf("Malloc Failed!\n");
return 0;
}
vsexp(len, src, dst);
/**
* Output dst:
* 0.0 inf nan 7.389056205749512
*
*/
Fortran interface:
INTEGER :: LEN = 2
REAL(4) SRC(2)
REAL(4) DST(2)
DATA SRC /1.0, 2.0/
CALL VSPOW(LEN, SRC, DST)
!
! OUTPUT DST:
! 0.0 7.389056205749512
!
Parent topic: Function Syntax