linalg.tensorinv
Description
The result is an inverse for a relative to the tensordot operation tensordot(a, b, ind), i. e., up to floating-point accuracy, tensordot(tensorinv(a), a, ind) is the "identity" tensor for the tensordot operation.
Mandatory Input Parameters
Parameter |
Type |
Description |
|---|---|---|
a |
array_like |
Tensor to "invert". Its shape must be "square", i. e., prod(a.shape[:ind]) == prod(a.shape[ind:]). |
Optional Input Parameters
Parameter |
Type |
Default Value |
Description |
|---|---|---|---|
ind |
int |
2 |
Number of first indices that are involved in the inverse sum. It must be a positive integer. |
Return Value
Type |
Description |
|---|---|
ndarray |
a's tensordot inverse. Shape: a.shape[ind:] + a.shape[:ind] |
Examples
>>> import numpy as np >>> a = np.eye(4*6) >>> a.shape = (4, 6, 8, 3) >>> >>> ainv = np.linalg.tensorinv(a, ind=2) >>> ainv.shape (8, 3, 4, 6) >>> >>> b = np.random.randn(4, 6) >>> np.allclose(np.tensordot(ainv,b), np.linalg.tensorsolve(a,b)) True >>> >>> a = np.eye(4*6) >>> a.shape = (24, 8, 3) >>> ainv = np.linalg.tensorinv(a, ind=1) >>> ainv.shape (8, 3, 24) >>> >>> b = np.random.randn(24) >>> np.allclose(np.tensordot(ainv,b,1), np.linalg.tensorsolve(a,b)) True >>>
Parent topic: Linear Algebra Functions