scalbn
Compute the result of x * 2^y.
Interface Definition
C interface:
float scalbnf(float x, int y);
double scalbn(double x, int y);
long double scalbnl(long double x, int y);
Parameters
Parameter |
Type |
Description |
Input/Output |
|---|---|---|---|
x |
|
Floating-point value of the input data. |
Input |
y |
|
Integer value of the input data |
Input |
Return Value
- The result of x * 2^y is returned. If an overflow occurs, +∞ or -∞ is returned (the sign is the same as that of x).
Dependency
C: "km_l9.h"
Example
C interface:
// typical usage
double x1 = 0.0, x2 = -0.0, x3 = 2.0;
long int y1 = 2, y2 = 3, y3 = 4, y4 = 5, y5 = 1100;
// special handing
double a = INFINITY, b = -INFINITY, c = NAN;
printf("scalbn(0.0, 2) = %.15f\n", scalbn(x1, y1));
printf("scalbn(-0.0, 3) = %.15f\n", scalbn(x2, y2));
printf("scalbn(2.0, 4) = %.15f\n", scalbn(x3, y3));
printf("scalbn(2.0, 5) = %.15f\n", scalbn(x3, y4));
printf("scalbn(2.0, 1100) = %.15f\n", scalbn(x3, y5));
printf("scalbn(INFINITY, 2) = %.15f\n", scalbn(a, y1));
printf("scalbn(-INFINITY, 2) = %.15f\n", scalbn(b, y1));
printf("scalbn(NAN, 2) = %.15f\n", scalbn(c, y1));
/*
* scalbn(0.0, 2) = 0.000000000000000
* scalbn(-0.0, 3) = -0.000000000000000
* scalbn(2.0, 4) = 32.000000000000000
* scalbn(2.0, 5) = 64.000000000000000
* scalbn(2.0, 1100) = inf
* scalbn(INFINITY, 2) = inf
* scalbn(-INFINITY, 2) = -inf
* scalbn(NAN, 2) = nan
*/
Parent topic: Exponential and Logarithmic Functions