v?exp
Compute the element-wise base-e exponential of a vector.
Interface Definition
C interface:
void vsexp(const int len, const float* src, float* dst);
void vdexp(const int len, const double* src, double* dst);
void vcexp(const int len, const float complex *src, float complex *dst);
void vzexp(const int len, const double complex *src, double complex *dst);
Fortran interface:
CALL VSEXP(LEN, SRC, DST);
CALL VDEXP(LEN, SRC, DST);
Parameters
Parameter |
Type |
Description |
Input/Output |
|---|---|---|---|
len |
Integer |
Number of elements in the input vector. If len ≤ 0, the system displays a message indicating that the value of len is invalid. |
Input |
src |
|
Input vector src with length len. If the pointer is null, the system prompts a null pointer error. |
Input |
dst |
|
Output vector dst with length len. If the pointer is null, the system prompts a null pointer error. |
Output |
Return Value
Return the result of 
. For special values, see the following table.
Input Value (src) |
Output Value (dst) |
|---|---|
+0 |
+1 |
-0 |
+1 |
-inf |
+0 |
+inf |
+inf |
nan |
nan |
Dependencies
C: "kvml.h"
Fortran: "kvml.f03"
Examples
C interface:
int i, len = 4;
float src[len] = {0.0f, INFINITY, NAN, 2.0f};
float* dst = (float*)malloc(sizeof(float) * len);
if (dst == NULL) {
printf("Malloc Failed!\n");
return 0;
}
vsexp(len, src, dst);
/**
* Output dst:
* 0.0 inf nan 7.389056205749512
*
*/
Fortran interface:
INTEGER :: LEN = 2
REAL(4) SRC(2)
REAL(4) DST(2)
DATA SRC /1.0, 2.0/
CALL VSPOW(LEN, SRC, DST)
!
! OUTPUT DST:
! 0.0 7.389056205749512
!